InLine καλώδιο TAE-F γερμανικό / RJ45 8P2C 2m

The InLine TAE-F German / RJ45 8P2C Cable (2 m) connects a TAE-F telephone wall socket directly to an RJ45 port on devices such as routers. It is a 2-wire cable designed for a direct connection without a splitter and is suitable for models like the FRITZ!Box 7170 and 7270. The cable has a TAE-F plug on one end and an RJ45 8P2C plug on the other and is available in black.

Advantages

This adapter cable provides a straightforward direct connection between a German TAE-F socket and an RJ45 input, supporting reliable voice/data transmission over two wires. Its 2 metre length offers flexibility for typical home and small office installations while keeping cable runs tidy. The fixed, moulded connectors reduce the risk of loose contacts and the cable is compatible with common router models that accept a 2-wire TAE to RJ45 wiring.

Suitable for

• Connecting FRITZ!Box 7170 or 7270 directly to a TAE-F wall socket
• Direct telephone line connection to routers without using a splitter
• Short home or small office installations where a 2 m cable length is sufficient

Key specifications

• Connector 1: TAE-F
• Connector 2: RJ45 (8P2C), wired for 2-wire connection
• Length: 2 m
• Colour: Black
• Brand: InLine
• MPN: 18502
• EAN: 4043718187553

How to use

Insert the TAE-F plug into the TAE-F telephone wall socket and connect the RJ45 8P2C plug to the corresponding RJ45 port on the router or device. Ensure the router model supports a direct 2-wire TAE to RJ45 connection (for example FRITZ!Box 7170/7270). Route the cable to avoid sharp bends and secure it to prevent strain on the connectors.

Recommendations

Use this cable for short-distance, direct connections between a TAE-F wall jack and a router. Do not use it as a replacement for network Ethernet cables; it is intended for voice/phone-line wiring where a 2-wire TAE to RJ45 connection is required. Avoid exposure to excessive moisture and mechanical stress to preserve connector integrity.